Sulfur oxide (6) with a mass of 8 g was dissolved in 92. Sulfur oxide (6) with a mass of 8 g was dissolved in 92 g of water. Determine the mass fraction of sulfuric acid in the resulting solution.
Let’s find the amount of SO3 by the formula:
n = m: M.
M (SO3) = 80 g / mol.
n = 8 g: 80 g / mol = 0.1 mol.
Let’s find the amount of substance H2O by the formula:
M (H2O) = 18 g / mol.
n = 92 g: 18 g / mol = 5.11 mol (excess).
Let’s compose the reaction equation, find the quantitative ratios of substances.
SO3 + H2O = H2SO4.
According to the reaction equation, there is 1 mol of H2SO4 for 1 mol of SO3. Substances are in quantitative ratios 1: 1.
n (H2SO4) = n (SO3) = 0.1 mol.
Let’s find the mass of H2SO4.
m = n × M,
M (H2SO4) = 98 g / mol.
m = 0.1 mol × 98 g / mol = 9.8 g.
W = m (substance): m (solution) × 100%,
m (solution) = 92 g + 8 g = 100 g.
W = (9.8: 100) × 100% = 9.8%.
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