Sulfur oxide was passed through barium hydroxide weighing 15 grams. Determine what salt is formed in what quantity.

Let’s find the amount of substance Ba (OH) 2.

M (Ba (OH) 2) = 171 g / mol.

n = m: M.

n (Ba (OH) 2) = 15 g: 171 g / mol = 0.087 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

Ba (OH) 2 + SO3 = BaSO4 + H2O.

According to the reaction equation, 1 mol of Ba (OH) 2 accounts for 1 mol of SO3, 1 mol of BaSO4. The substances are in quantitative ratios of 1: 1.

Let’s find the mass of BaSO4.

m = n × M,

M (BaSO4) = 233 g / mol.

m = 0.087 mol × 233 g / mol = 20.27 g.

Answer: 20.27 g; barium sulfate.