Sulfuric acid is poured into the right knee of the communicating vessels, and water is poured into the left

Sulfuric acid is poured into the right knee of the communicating vessels, and water is poured into the left. how much is the water level higher than the sulfuric acid level if the water level is 36 cm high?

Given:

h1 = 36 centimeters = 0.36 meters – water level in communicating vessels;

g = 10 N / kg – acceleration of gravity;

ro1 = 1000 kg / m ^ 3 – water density;

ro2 = 1840 kg / m ^ 3 – density of sulfuric acid.

It is required to determine dh (meters) – how much the water level is higher than the level of sulfuric acid in the communicating vessels.

The water pressure will be equal to the sulfuric acid pressure:

Pwater = Psulfuric acid;

ro1 * h1 * g = ro2 * h2 * g;

ro1 * h1 = ro2 * h2;

h2 = ro1 * h1 / ro2 = 1000 * 0.36 / 1840 = 360/1840 = 0.2 meters.

Then:

dh = h1 – h2 = 0.36 – 0.2 = 0.16 meters (16 centimeters).

Answer: the water level will be 16 centimeters higher.