Sulfuric acid was added to 120 grams of barium chloride solution with a mass fraction of 15%.

Sulfuric acid was added to 120 grams of barium chloride solution with a mass fraction of 15%. Find the mass of the precipitated sediment.

BaCl2 + H2SO4 = BaSO4 + 2HCl.

Knowing the mass of the solution and the mass fraction of barium chloride, you can calculate its mass by the formula:

w = m (salt) / m (solution) * 100%.

15% = x / 120 * 100%.

From this we get that x = 120 * 15/100 = 18 g.

Now you can find the mass of the precipitated BaSO4 precipitate, given that from 208 g of BaCl2, 233 g of BaSO4 are formed (since we know the molar masses):

18 g – x g

208 g – 233 g

x = 18 * 233/208 = 20.2 g.

Therefore, the mass of BaSO4 is 20.2 g.