Sulfuric acid weighing 9.8 g. Interacting with sodium hydroxide forms a salt. The number of moles of sodium

Sulfuric acid weighing 9.8 g. Interacting with sodium hydroxide forms a salt. The number of moles of sodium sulfate is equal.

Let’s execute the solution:
1. According to the condition of the problem, we compose the equation:
m = 9.8 g. Y -?
H2SO4 + 2NaOH = Na2SO4 + 2H2O – ion exchange, sodium sulfate obtained;
1 mol 1 mol;
2. Determine the amount of the original substance, if its mass is known:
Y (H2SO4) = m / M = 9.8 / 98 = 0.1 mol;
Y (Na2SO4) = 0.1 mol since the amount of these substances is equal to 1 mol according to the equation.
Answer: sodium sulfate was formed in an amount of 0.1 mol.