Superman stands in a window 30 m above the street. a ball that is dropped from a window 15 m higher flies past.

| September 4, 2021 | education

Superman stands in a window 30 m above the street. a ball that is dropped from a window 15 m higher flies past. With what constant acceleration (from rest) should the superman begin to move in order to catch the falling ball?

Task data: hc (height at which Superman is) = 30 m; h0 (height above Superman, at which the ball was located) = 15 m.

Constants: g (acceleration due to gravity) = 9.81 m / s2.

1) Duration of the ball falling to the Superman level: t1 = √ (2h0 / g) = √ (2 * 15 / 9.81) = 1.749 s.

2) The total duration of the ball falling: t = √ (2h / g) = (√ (2 * (h + h0) / g)) = √ (2 * (30 + 15) / 9.81) = 3.029 s.

3) The duration of Superman’s movement: tc = t – t1 = 3.029 – 1.749 = 1.28 s.

4) Superman acceleration: a = 2 * hc / tc ^ 2 = 2 * 30 / 1.28 ^ 2 = 36.62 m / s2.



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