Tangent AB is drawn through point B of a circle with center C. Find the BAC angle if the BAC angle is 42 °

Tangent AB will be perpendicular to the radius of the circle CB. Therefore, as a result of the constructed constructions, we obtain a right-angled triangle ABC, in which the straight line ∠ ABC.

∠ABC = 90 °.

∠BCA = 42 °.

So ∠BAC = 180 ° – ∠ABC – ∠BCA = 180 ° – 90 ° – 42 ° = 48 °.

Answer: ∠BAC = 48 °.



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