Technical soda ash with a mass of 106 g, containing 90% sodium carbonate Na2CO3

Technical soda ash with a mass of 106 g, containing 90% sodium carbonate Na2CO3, interacts with an excess of hydrochloric acid HCl. Calculate the volume and mass of carbon dioxide (CO2) produced.

Let’s get rid of impurities:
106 g – 100%

x g – 90%

Hence, x = 106 * 90/100 = 95.4 g Na2CO3

We compose the reaction equation:
Na2CO3 + 2 НСl = 2 NaCl + CO2 + H2O

According to the equation: Na2CO3 and CO2 – 1 mol each

We find their masses by the formula: m = n * M

m (Na2CO3) = 1 mol * (23 * 2 + 12 + 16 * 3) = 106 g

m (CO2) = 1 mol * (12 + 16 * 2) = 44 g

Let’s calculate the mass of CO2:
95.4 g Na2CO3 – x g CO2

106 g Na2CO3 – 44 g CO2

Hence, x = 95.4 * 44/106 = 39.6 g.

Let’s calculate the volume of CO2 using the formula:
V = Vm * m / M = 22.4 * 39.6 / 44 = 20.16 liters.



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