Technical soda ash with a mass of 106 g, containing 90% sodium carbonate Na2CO3
Technical soda ash with a mass of 106 g, containing 90% sodium carbonate Na2CO3, interacts with an excess of hydrochloric acid HCl. Calculate the volume and mass of carbon dioxide (CO2) produced.
Let’s get rid of impurities:
106 g – 100%
x g – 90%
Hence, x = 106 * 90/100 = 95.4 g Na2CO3
We compose the reaction equation:
Na2CO3 + 2 НСl = 2 NaCl + CO2 + H2O
According to the equation: Na2CO3 and CO2 – 1 mol each
We find their masses by the formula: m = n * M
m (Na2CO3) = 1 mol * (23 * 2 + 12 + 16 * 3) = 106 g
m (CO2) = 1 mol * (12 + 16 * 2) = 44 g
Let’s calculate the mass of CO2:
95.4 g Na2CO3 – x g CO2
106 g Na2CO3 – 44 g CO2
Hence, x = 95.4 * 44/106 = 39.6 g.
Let’s calculate the volume of CO2 using the formula:
V = Vm * m / M = 22.4 * 39.6 / 44 = 20.16 liters.