Technical soda, the mass fraction of impurities in which is 25%, was treated with hydrochloric acid. 10 mol of CO2 was released.

Technical soda, the mass fraction of impurities in which is 25%, was treated with hydrochloric acid. 10 mol of CO2 was released. Calculate the mass of technical soda that has entered into a chemical reaction

Given:
w approx (Na2CO3) = 25%
n (CO2) = 10 mol
To find:
m mixture (Na2CO3)
Decision:
Na2CO3 + 2HCl = H2O + CO2 + 2NaCl
w is clean. islands (Na2CO3) = 100% -25% = 75% = 0.75%
n (CO2): n (Na2CO3) = 1: 1
n (Na2CO3) = 10 mol
m in islands ((Na2CO3) = n * M = 10 mol * 106 g / mol = 1060 g
m mixture (Na2CO3) = m water / w pure. in-va = 1060 g / 0.75 = 1413 g
Answer: 1413 g