Technical soda, the mass fraction of impurities in which is 25%, was treated with hydrochloric acid. 5 mol of CO2 was released.

Technical soda, the mass fraction of impurities in which is 25%, was treated with hydrochloric acid. 5 mol of CO2 was released. Calculate the mass of technical soda that has entered into a chemical reaction.

Given:
w approx (Na2CO3) = 25%
n (CO2) = 5 mol
To find:
m mixture (Na2CO3)
Decision
Na2CO3 + 2HCl = 2NaCl + H2O + CO2
n (CO2): n (Na2CO3) = 1: 1
n (Na2CO3) = 5 mol
m in islands (Na2CO3) = n * M = 5 mol * 106 g / mol = 530 g
w is clean. islands (Na2CO3) = 100% -25% = 75% = 0.75
m mixture (Na2CO3) = m in-va / w = 530 g / 0.75 = 706.7 g
Answer: 706.7 g