Ten drops of mercury, volume V = 1.0 mm3 each, merged into one. Determine the mass of the resulting drop.

univerkov | September 15, 2021 | education

Problem data: n (number of drops of mercury) = 10 drops; V1 (volume of one drop of mercury) = 1 mm3 (1 * 10-9 m3).

Reference values: ρ (density of mercury) = 13600 kg / m3.

The mass of the resulting drop of mercury is determined by the formula: m = ρ * V = ρ * n * V1.

Let’s calculate: m = 13600 * 10 * 1 * 10-9 = 0.000136 kg = 136 mg.

Answer: The mass of the resulting drop of mercury is 136 mg.

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