The 10 kW engine consumes 1.5 kg of diesel fuel per hour. determine the efficiency of the engine (q = 4.2 * 10 ^ 7j \ kg)
| November 25, 2020 | education
N = 1kW = 10000W
t = 60 min
m = 1.5kg
q = 4.2 x 10 ^ 7 J / kg
Decision:
A = N x t
A = 10000 x 60 = 600000 J
Q2 = q x m
Q2 = 42000000 x 1.5 = 63000000J
n = Q1 / Q2
n = 600000/63000000 x 100% = 0.952%
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
