The 15 cm long spring has a stiffness factor of 15 N / m. How long will the spring stretch under the action of the 3H force?

Data: l (spring length) = 15 cm; k (stiffness coefficient) = 15 N / m; F (acting force) = 3 N.

To find the tension of the taken spring, we apply Hooke’s law: F = Fcont = k * Δx and Δx = F / k.

Calculation: Δx = 3/15 = 0.2 m.

Answer: The taken spring will stretch 0.2 m under the action of a force of 3 N.



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