The 2 angles of the triangle are 50 and 70 degrees. Find the angle between the bisectors of these angles.

Let’s call the triangle ABC, in which the angle A = 50 °, the angle B = 70 °. The bisectors AH and BE pass through the corners A and B, intersecting at point K. The triangle AKB is obtained. You need to find the angle of the AKB.

A bisector is a ray that bisects an angle, so:

SAN = HAB = 1/2 A;

SAN = HAB = 1/2 50 °;

CAN = HAB = 25 °;

ABE = EBC = 1/2 B;

ABE = EBC = 1/2 70 °;

ABE = EBC = 35 °;

The sum of the angles in a triangle is always 180 °, knowing the angles HAB and ABE of the triangle AKB, we find the angle AKB:

AKB = 180 ° – 25 ° – 35 °;

AKB = 120 ° – the angle between the bisectors.