The 60 ° center angle AOB rests on chord AB of length 3. Find the radius of the circle.

The first way.

The AOB triangle is isosceles, since ОА = ОВ = R, and since the AOB angle = 60, the AOB triangle is equilateral.

Then AO = AB = OB = R = 3 cm.

Second way.

We use the formula for the length of a chord of a circle in terms of the radius of the circle.

L = 2 * R * Sin (AOB / 2), where L = the length of the chord AB, R is the radius of the circle, AOB is the central angle that rests on the chord AB.

3 = 2 * R * Sin (60/2).

3 = 2 * R * Sin30.

2 * R = 3 / (1/2) = 6.

R = 6/2 = 3.

Answer: The radius of the circle is 3 cm.



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