The 98 ohm wire was cut into several identical pieces and the resulting pieces were connected in parallel.

The 98 ohm wire was cut into several identical pieces and the resulting pieces were connected in parallel. We measured the resistance of this section – it turned out to be 2 ohms. How many pieces did you cut the wire into?

Before cutting, we can assume that the conductors are connected in series: R1 = r * n, where R is the resistance of the whole conductor (R = 98 Ohm), r is the resistance of one part.
r = R1 / n.
For parallel connection:
1 / R2 = 1 / r1 + 1 / r2 + … + 1 / rn; R2 is the resistance of the section (R = 2 Ohm), r1, r2, … is the resistance of one section.
Since R1 = R2 … = Rn, the total resistance R2 = r / n.
r = R2 * n.
Then:
R1 / n = R2 * n.
n ^ 2 = R1 / R2;
n = √ (R1 / R2) = √ (98/2) = √ (49) = 7.
Answer: The wire was cut into 7 pieces.