The ABC triangle conducted BF bisectris. Find the angle C if angle a = 39 degrees, angle AFB = 78 degrees.

From the triangle ABF angle AF = 180 ° – (BAF + AFB) = 180 ° – (39 ° + 78 °) = 180 ° – 117 ° = 63 °.

Since bf bisectris, then the angle CBF = ABF = 63 °. BFC angle adjacent with AFB angle, from here we have BFC = 180 ° – BFA = 180 ° – 78 ° = 102 °.

From the triangle BFC angle of FCB = 180 ° – (FBC + BFC) = 180 ° – (63 ° + 102 °) = 180 ° – 165 ° = 15 °.

Answer: Corner C = 15 ° degrees.



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