The ABC triangle inscribes the circle. AC, respectively. Bn = 4cm, nc = 6cm

The ABC triangle inscribes the circle. AC, respectively. Bn = 4cm, nc = 6cm, the perimeter of the triangle is 34cm, find the lengths of the segments of AM and AL.

Since the segments of tangents to the circle carried out from one point are equal, then

BM = BN = 4 cm, CN = C = 6 cm, AM = Al.

The perimeter of the ABS triangle will be equal to: Ravox = AB + BS + AC = AM + BM + BN + CN + AL + CL.

Let am and AL = x see

Then Ravox = X + BM + BN + CN + X + CL.

34 = 2 * x + 4 + 4 + 6 + 6.

2 * x = 34 – 20 = 14 cm.

X = 14/2 = 7 cm

AM = Al = 7 cm.

Answer: AM = Al = 7 cm.