The absolute temperature of the refrigerator of an ideal heat engine is three times less than the temperature of the heater.
| June 21, 2021 | education
The absolute temperature of the refrigerator of an ideal heat engine is three times less than the temperature of the heater. The machine receives 600 J of heat from the heater in one cycle. What is the useful work done by the machine in one cycle?
Data: Тх (refrigerator temperature) = 3Тн (heater temperature); Qs (the amount of heat that a heat engine receives in one cycle) = 600 J.
The useful work that the heat engine under consideration will perform in one cycle is determined from the equality: η = (Тн – Тх) / Тн = Qп / Qз, whence Qп = (Тн – Тх) * Qз / Тн = (3Тн – Тх) * Qз / 3Тх = 2Тх * Qz / 3Тх = 2 * Qz / 3.
Calculation: Qp = 2 * 600/3 = 400 J.
Answer: In one cycle, the heat engine under consideration will perform 400 J of useful work.
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