The acceleration of gravity on the surface of the Earth is g = 9.81 m / s², and its radius is R = 6.371 * 10 ^ 6.

| May 18, 2021 | education

The acceleration of gravity on the surface of the Earth is g = 9.81 m / s², and its radius is R = 6.371 * 10 ^ 6. The satellite revolves around the Earth in a circular orbit at an altitude of h = 3.2 * 10 ^ 6 m. What is the speed of the satellite in orbit?

To determine the value of the speed of the satellite in question around the Earth, we apply the formula: V = √ (g * Rz ^ 2 / (Rz + h)).

Constants and variables: g – gravitational acceleration (g = 9.81 m / s2); Rz – radius of the Earth (by condition Rz = 6.371 * 106 m); h – satellite height (h = 3.2 * 10 ^ 6 m).

Calculation: V = √ (g * Rz ^ 2 / (Rz + h)) = √ (9.81 * (6.371 * 10 ^ 6) ^ 2 / (6.371 * 10 ^ 6 + 3.2 * 10 ^ 6) ) = 6450 m / s = 6.45 km / s.

Answer: The speed of the satellite in question is 6.45 km / s.



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