The acute angle of an isosceles trapezoid is 45 °, and the height drawn from the top of the obtuse angle divides
| June 2, 2021 | education
The acute angle of an isosceles trapezoid is 45 °, and the height drawn from the top of the obtuse angle divides the bases into segments 14 and 34 cm. Find the area of the trapezoid.
1. Determine the length of the upper base.
34 – 14 * 2 = 34 – 28 = 6 centimeters.
2. Since the leg formed by the height of the trapezoid of the triangle is opposite the angle equal to the angle against which the height, and its length is 14 centimeters, then the length of the height is 14 centimeters.
3. What is the area of the trapezoid?
(34 + 14 * 2 + 6) / 2 * 14 = (34 + 28 + 6) / 2 * 14 = 68/2 * 14 = 34 * 14 = 476 cm2.
Answer: 476 square centimeters is the area of the trapezoid.
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