The acute angle of the parallelogram = 30 degrees, and the heights drawn
The acute angle of the parallelogram = 30 degrees, and the heights drawn from the top of the obtuse angle are 4cm and 6cm. Find the area of a parallelogram
1. Vertices of the parallelogram A, B, C, D. ∠A = 30 °. ∠В – stupid. Height ВK = 4 cm – drawn to the AD side. Height BE = 6 cm – drawn to the side of the CD.
2. In a right-angled triangle AВK, the leg ВK (parallelogram height) is opposite to ∠A, equal to 30 °. Therefore, according to the properties of this triangle, ВK = 1 / 2AB.
Hence, AB = 2x BK = 2 x 4 = 8 cm.
3. According to the properties of a parallelogram, its opposite sides are equal.
That is, AB = CD = 8 cm.
4. Calculate the area (S) of a given geometric figure:
S = CD x BE = 8 x 6 = 48 cm².
Answer: the area of the parallelogram is 48 cm².