The acute angles of a right-angled triangle are 20∘ and 70∘. Find the angle between the height

The acute angles of a right-angled triangle are 20∘ and 70∘. Find the angle between the height and the bisector drawn from the vertex of the right angle.

Let’s designate our triangle ABC, height CH, bisector CK. Let’s solve the problem in different ways.
Option 1.
Consider a right-angled triangle CВН.
∠ НСВ = 90 ° – ∠ СНВ = 90 ° – 70 ° = 20 °.
Consider the КСВ angle, it is equal to 45 ° (CK is the bisector),
Find the angle KCH.
∠ КСН = ∠ КСВ – ∠ СНВ = 45 ° – 20 ° = 25 °.
Option 2.
Consider a right-angled triangle AHC.
∠ ACH = 90 ° – ∠ CAH = 90 ° – 20 ° = 70 °.
Similarly to the first option, we find the KCH angle.
∠ КСH = ∠ АCH – ∠ АСК = 70 ° – 45 ° = 25 °.
Answer: the angle between the height and the bisector is 25 °.