The adjacent sides of the parallelogram are 10 cm and 15 cm, and the angle between them

The adjacent sides of the parallelogram are 10 cm and 15 cm, and the angle between them is 30 degrees. find the area of the parallelogram.

In parallelogram ABCD, sides AB = CD = 10 cm; AD = BC = 15 cm; angle A = 30 °;

1) Since the sides of the parallelogram AB and AD and the angle A between them are known, the area can be calculated by the formula:

S = AB * AD * sin A; sin 30 ° = 0.5;

S = 10 * 15 * 0.5 = 75 (cm²).

2) S = 1/2 AD * BH, where BH is the height of the parallelogram;

BH = 1/2 AB, as it lies opposite an angle of 30 °;

BH = 5 cm;

S = 1/2 * 10 * 15 = 75 (cm²).