The air capacitor was charged from a constant voltage source and then disconnected.
| July 22, 2021 | education
The air capacitor was charged from a constant voltage source and then disconnected. The distance between the plates was doubled. What happened to the energy of the capacitor’s electric field?
To calculate the change in the energy of the electric field of the taken capacitor, we use the ratio: k = Wpk / Wpn = 0.5 * q * Uk / (0.5 * q * Un) = Uk / Un = E * dk / (E * dn) = dк / dн.
The ratio of the variables: dk (final distance between the plates) = 2dn (initial distance).
Calculation: k = dk / dn = 2dn / dn = 2 p.
Answer: The energy of the electric field of the taken capacitor will increase 2 times.
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