The air is under a pressure of 10 ^ 5 pascals and occupies a volume of 0.6 m3, what work will

The air is under a pressure of 10 ^ 5 pascals and occupies a volume of 0.6 m3, what work will be done to reduce its volume to 0.2 m3.

To find out the value of the work performed with a decrease in the volume of air taken, we apply the formula: A = P * ΔV = P * (Vn – Vk).

Data: P – constant pressure of the taken air (P = 10 ^ 5 Pa); Vн – initial air volume (Vн = 0.6 m3); Vн – final (reduced) air volume (Vн = 0.2 m3).

Calculation: A = P * (Vn – Vk) = 10 ^ 5 * (0.6 – 0.2) = 40 * 10 ^ 3 J = 40 kJ.

Answer: To compress the taken air to 0.2 m3, it will take 40 kJ work.