The air is under a pressure of 100 kPa and occupies a volume of 0.6 m3. What work will be done

The air is under a pressure of 100 kPa and occupies a volume of 0.6 m3. What work will be done if its volume is reduced to 0.2 m3?

To find the work performed with a decrease in the volume of air taken, use the formula: Avn = P * ΔV = P * (Vn – Vk).

Variables: P – constant pressure of the taken air (P = 100 kPa = 10 ^ 5 Pa); Vн – volume before compression (Vн = 0.6 m3); Vк – final volume (Vк = 0.2 m3).

Let’s make a calculation: Avn = 10 ^ 5 * (0.6 – 0.2) = 40 * 10 ^ 3 J.

Answer: With a decrease in the volume of taken air, work of 40 kJ was performed.