The air is under a pressure of 50.5 kPa. How will its volume change if the pressure becomes equal to 0.206 MPa?

P1 = 50.5 kPa = 50.5 * 10 ^ 3 Pascal – initial air pressure;

P2 = 0.206 MPa = 0.206 * 10 ^ 6 Pascal – final air pressure;

T1 = T2 = const – the process temperature is constant.

It is required to determine how to change the air volume with increasing pressure V2 / V1.

Since, according to the condition of the problem, the process took place at a constant temperature, then:

P1 * V1 = P2 * V2;

P1 * V1 / P2 = V2;

V2 / V1 = P1 / P2 = 50.5 * 10 ^ 3 / (0.206 * 10 ^ 6) = 245 * 10 ^ -3 = 0.245 times.

Answer: the air volume will decrease 0.245 times.