The air volume is 60 m3, the specific heat capacity is 1000 J kg degrees, the air density is 1.29 kg m3.

The air volume is 60 m3, the specific heat capacity is 1000 J kg degrees, the air density is 1.29 kg m3. How much heat is needed to heat it 22 degrees.

Initial formula: Q = m × c × (t1-t2)
In the condition there is no mass m, but there is a volume V and a density p, so we express the mass of them: p = m ÷ V (original formula) m = p × V m = 60 × 1.29 = 77.4 kg
Also, there is no t2 in the condition, but since we understand that the body heats up from 0 ° С for t2 we take 0
Then we substitute everything according to the formula Q = m × c × (t1-t2):
Q = 77.4 × 1000 × 22 = 1 702 800J
Answer: 1.7mJ