The airplane is affected by an air resistance force equal to 4.32 kN. What is the power

The airplane is affected by an air resistance force equal to 4.32 kN. What is the power of an aircraft’s engines if it flies 1,500 km in 2 hours in a uniform motion?

Data: Fc (air resistance force) = 4.32 kN (4.32 * 10 ^ 3 N); the plane moves uniformly (a = 0; m * a = 0 = F + Fc; F (engine thrust force) = Fc); t (duration of aircraft movement) = 2 hours (2 * 3600 s; 7200 s); S (distance the plane flew) = 1500 km (1500 * 10 ^ 3 m).

The power of the aircraft engines is determined by the formula: N = F * V = F * S / t.

Let’s make the calculation: N = 4.32 * 10 ^ 3 * 1500 * 10 ^ 3/7200 = 0.9 * 10 ^ 6 W (900 kW).

Answer: The power of the aircraft engines is 900 kW.