The alkane has a vapor density in air of 2.97. Determine the alkane formula.

M (СnH2n + 2) = 29g / mol * 2.97 = 86g / mol.

Substitute the resulting value into the formula, then:

12n + 2n + 2 = 86

14n + 2 = 86

14n = 86-2

14n = 84

n = 84/14

n = 6

Therefore, the molecular formula of the substance is: C6H14



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