The alloy consists of 19 hours of aluminum and 2 hours of magnesium, what is the mass

The alloy consists of 19 hours of aluminum and 2 hours of magnesium, what is the mass of the alloy if magnesium is 34 less than aluminum.

1. Let’s find the difference between the proportion of aluminum and magnesium:
19 – 2 = 17 pieces.
2. Since aluminum in the alloy is 34 g more, then this difference is 17 parts, then we can find the mass of 1/17 part of the alloy:
34/17 = 2 g.
3. Find the number of shares in the alloy:
19 + 2 = 21.
4. Calculate the weight of the alloy by multiplying the mass of one part by 21:
21 * 2 g = 42 g.
Answer: The alloy weighs 42 g.



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