The alloy consists of 19 parts aluminum and 2 parts magnesium (by weight).

The alloy consists of 19 parts aluminum and 2 parts magnesium (by weight). What is the mass of an alloy if it contains 34 kg less magnesium than aluminum?

Let one part of the alloy be equal to x kilograms. The alloy consists of 19 parts of aluminum or 19 kilograms of aluminum and 2 parts of magnesium or 2 kilograms of magnesium. According to the condition of the problem, it is known that in the alloy there is less magnesium than aluminum by (19x – 2x) kilograms or 34 kilograms. Let’s make an equation and solve it.

19x – 2x = 34;

17x = 34;

x = 34: 17;

x = 2 (kg) is the mass of one part of the alloy;

19x = 2 * 19 = 38 (kg) – the mass of aluminum;

2x = 2 * 2 = 4 (kg) – the mass of magnesium.

Let’s find the mass of the alloy.

38 + 4 = 42 (kg).

Answer. 42 kilograms.