The alloy consists of silver, copper and gold. The ratio of the values is 2: 1: 7, respectively.
The alloy consists of silver, copper and gold. The ratio of the values is 2: 1: 7, respectively. How many grams of each metal is contained in 640 g of the alloy?
1. Let’s find how many parts are in the alloy:
2 + 1 + 7 = 10.
2. Find how much one part weighs.
640: 10 = 64.
3. Let’s find how many grams of each metal is included in the alloy, if the ratio of silver, copper and gold is 2: 1: 7.
4. Find the mass of silver, knowing that it is 2 parts.
64 x 2 = 128 g.
5. Find the mass of copper (1 part) – 64 g.
6. Find the mass of gold (7 parts):
64 x 7 = 448 g.
128 g + 64 g + 448 g = 640 g.
Second way.
Let us denote the mass of the metal by x.
2 x – weight of silver.
x is the mass of copper.
7 x is the mass of gold.
Let’s make an equation.
2x + x + 7x = 640.
10x = 640,
x = 640: 10,
x = 64.
64 x 2 = 128.
64 x 7 = 448.
Answer: 64 g; 128 g; 448 BC
