The alloy consists of tin weighing 2.92 kg and lead weighing 1.13 kg.

The alloy consists of tin weighing 2.92 kg and lead weighing 1.13 kg. What is the density of the alloy if we assume that the volume of the alloy is equal to the sum of the volumes of its constituent parts?

mo = 2.92 kg.

mw = 1.13 kg.

ρо = 7300 kg / m ^ 3.

ρw = 11300 kg / m ^ 3.

V = Vо + Vw.

ρ -?

The density of the substance ρ is determined by the formula: ρ = m / V, where m is the mass of the alloy, V is the volume of the alloy.

The mass of the alloy will be the sum: m = mo + mw.

The volume of the alloy will be the sum: V = Vo + Vw.

The volumes of tin and lead are found by the formulas: Vо = mo / ro, Vw = mw / ρw.

ρ = (mo + mw) / (mo / ro + mw / ρw).

ρ = (2.92 kg + 1.13 kg) / (2.92 kg / 7300 kg / m ^ 3 + 1.13 kg / 11300 kg / m ^ 3) = 8100 kg / m ^ 3.

Answer: the density of the alloy is ρ = 8100 kg / m ^ 3.