The alloy contains 6 parts of zinc and 8 parts of iron. How much iron does it take to get 448 kg of alloy?

In order to find how much iron you need to take, in order to get 448 kg of alloy, we will compose and solve the equation.

And we also know that the alloy consists of zinc and iron and they are included in the composition in a ratio of 6: 8.

Let’s enter the coefficient of similarity k, then the weight of zinc in fame can be written as 6k, and iron as 8k.

We can now compose the following equation:

6k + 8k = 448;

We solve the linear equation:

k (6 + 8) = 448;

14k = 448;

k = 448: 14;

k = 32.

So, you need to take iron 8 * 32 = 256 kg.