The alloy is composed of 2 parts gold, 1 part platinum and 10 parts silver. How much gold

The alloy is composed of 2 parts gold, 1 part platinum and 10 parts silver. How much gold, platinum and silver is contained in an alloy weighing 910 g?

Since the alloy is divided into parts, it will not be difficult to solve this problem.

Based on this, we draw up an equation.

Let’s denote one part – x.

Based on the conditions of the problem, the following equation is obtained: 2x + 1x + 10x = 910.

Solving the equation: 13x = 910.

x = 910/13.

x = 70 (g) – constitutes one part of the alloy.

Gold takes 2 parts in the alloy – 2 * 70 = 140 (g).

Platinum one part – 1 * 70 = 70 (g).

Silver is 10 parts of the alloy – 10 * 70 = 700 (g).