The alloy weighing 800 g contains 60% zinc. 200 g of zinc was added to the alloy

The alloy weighing 800 g contains 60% zinc. 200 g of zinc was added to the alloy and remelted again. How much zinc is there in the new alloy?

800 g – 100%
60% – zinc – 480 g

Decision:
(800/100 * 60 = 480)
480 + 200 = 680 g in 1000 g alloy
(800 + 200 = 1000)

1000 g – 100%
680 g – zinc -? %
680 * 100/1000 = 68%

Answer: 68% of the zinc will be in the new alloy.

Method for solving the problem: proportions and percentages.



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