The alphabet consists of 12 characters, what is the information volume of the message in bytes, 64 characters long?

To encode one of 12 characters, 4 bits are required (we are looking for the closest power of two, considering that 1 bit allows you to encode 2 characters. We have a 12-character alphabet, so 2 ^ 4 = 16 is suitable).
Message size = 64 * 4 [bits] = 64 * 4/8 [bytes] = 32 [bytes]



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