The alphabet has a capacity of 64. How many KB of memory would it take to store 128

The alphabet has a capacity of 64. How many KB of memory would it take to store 128 pages of text with an average of 256 characters per page?

If the cardinality of the alphabet is 64 characters. The minimum number of bits required to encode one character in such an alphabet is 6 bits (2 ^ 6 = 64).
One page contains 256 characters, therefore, it will take 256 x 6 = 1536 bits to store it.
There are 128 pages in the text, 128 x 1536 = 196608 bits are needed to store them.
1 byte = 8 bits, so 196608 bits = 24576 bytes.
1 KB = 1024 bytes, so 24576 bytes = 24 KB.
Answer: To store the text you are looking for, you need 24 KB of memory.