The alphabet of some language consists of 64 characters. This alphabet was used to compose a text that takes

The alphabet of some language consists of 64 characters. This alphabet was used to compose a text that takes 2 pages, each page has 20 lines of 15 characters. Determine the size of the text (informational volume) in bytes.

If the source language (alphabet) consists of 64 characters, then a 5-bit binary code is required to store one character of such an alphabet (2 ^ 5 = 64).

The text on one page contains 20 * 15 = 300 characters (20 lines of 15 characters). Thus, two pages of text contain 300 * 2 = 600 characters.

It follows from this that its information capacity is 600 * 5 bits = 3000 bits.

1 byte = 8 bits, therefore 3000 bits = 3000: 8 = 375 bytes.