The aluminum ingot has a volume of 220 cubic dm. Determine its mass.

Let ρ be the density of aluminum, V – the volume of the aluminum ingot, m – the desired mass of the ingot. We know that m = ρ * V. Let’s convert the volume of the ingot from liters to cubic meters V = 220 dm cube. = 220/1000 = 0.22 cubic meters meters. Substitute numerical values into the formula (we know the volume from the condition, the density of aluminum is a tabular value) and we get, m = 0.22 m3 * 2712 kg / m3 = 596.64 kg. This means that the mass of the ingot is 594.64 kg.
Answer: 594.64 kg.