The aluminum winding of the electromagnet at a temperature of 0 ° C consumes 5 kW of power.

The aluminum winding of the electromagnet at a temperature of 0 ° C consumes 5 kW of power. What will be the power consumption if, during operation, the winding temperature rises to 60 ° C, and the voltage remains unchanged? What will happen if the current in the winding remains unchanged?

-for U = const:
P = (U ^ 2) / R, where P is the current power (P = 5 kW = 5000 W), U is the voltage in the network, R is the resistance of the winding.
-for I = const:
P = (I ^ 2) * R, where I is the current strength.
The resistance of the metal increases with increasing temperature:
R1 = R0 * (1 + α * ∆t), where R0 is the resistance at 0 ºС, α is the temperature coefficient of resistance (α = 0.0042 K ^ -1), ∆t is the temperature change (∆t = 60 ºС) …
-for U = const:
P1 = P0 * R0 / R1 = 5000 * R0 / (R0 * (1 + α * ∆t)) = 5000 / (1 + 0.0042 * 60) = 3994 W.
-for I = const:
P1 = P0 * R1 / R0 = 5000 * R0 * (1 + α * ∆t) / R0 = 5000 * (1 + 0.0042 * 60) = 6260 W.