The ammeter shows a current of 3 A. How many electrons have passed through its cross sections in 2 s?

Initial data: I (amperage shown by the ammeter) = 3 A; t (time of motion of electrons) = 2 s.

Reference values: according to the condition e (charge of one electron) = 1.6 * 10 ^ -19 Cl.

1) Determine the magnitude of the electric charge: q = I * t = 3 * 2 = 6 Cl.

2) Let’s calculate the number of electrons passing through the ammeter in 2 seconds: n = q / e = 6 / (1.6 * 10 ^ -19) = 3.75 * 10 ^ 19 electrons.

Answer: In 2 seconds, 3.75 * 10 ^ 19 electrons passed through the ammeter.