The ammeter shows that the current in the circuit is 3A. How many electrons passed in 2 seconds

The ammeter shows that the current in the circuit is 3A. How many electrons passed in 2 seconds through the cross section of the conductor?

Given:
I = 3 Amperes – current in the electrical circuit;
t = 2 seconds – time interval;
e = 1.6 * 10 ^ -19 Coulomb is the charge of one electron.
It is required to determine n – how many electrons have passed through the electrical circuit during the time interval t.
Let us find the total charge that passed through the electric circuit during the time interval t:
Q = I * t = 3 * 2 = 6 Pendant.
Then the number of electrons will be equal to:
n = Q / e = 6 / (1.6 * 10 ^ -19) = 6 * 10 ^ 19 / 1.6 = 3.75 * 10 ^ 19.
Answer: 3.75 * 10 ^ 19 electrons passed through the electrical circuit in 2 seconds.

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