The amount of heat equal to 900 kJ was transferred to an aluminum bar weighing 500 g

| May 27, 2021 | education

The amount of heat equal to 900 kJ was transferred to an aluminum bar weighing 500 g at a temperature of 20 oC. What will be the temperature of aluminum?

Given:

m = 500 grams = 0.5 kilograms – the mass of the aluminum bar;

T0 = 20 degrees Celsius – the initial temperature of the bar;

Q = 900 kJ = 900000 Joules – the amount of energy transferred to the bar;

c = 920 J / (kg * C) – specific heat capacity of aluminum.

It is required to determine T1 (degrees Celsius) – the temperature of the aluminum bar after heating.

Q = c * m * dT = c * m * (T1 – T0) = c * m * T1 – c * m * T0, hence:

c * m * T1 = Q + c * m * T0;

T1 = Q / (c * m) + T0 = 900000 / (0.5 * 920) + 20 =

= 900000/460 + 20 = 1956 + 20 = 1976 degrees.

Answer: the temperature of the aluminum bar will be equal to 1976 degrees.



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