The amount of heat released over a period of time △ t = 1.0 min on a resistor with a current
| September 9, 2021 | education
The amount of heat released over a period of time △ t = 1.0 min on a resistor with a current of Q = 8.0 kJ. Determine the current strength I in the resistor if its resistance is R = 10 Ohm.
Data: Δt (time span) = 1 min = 60 s; Q (released heat) = 8 kJ = 8 * 10 ^ 3 J; R (resistor resistance) = 10 ohms.
To determine the current in the specified resistor, we apply the formula: Q = I2 * R * Δt, whence we express: I = √ (Q / (R * Δt)) = √ (8 * 10 ^ 3 / (10 * 60)) = 3, 65 A.
Answer: A current of 3.65 A flows through the indicated resistor.
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