The amount of oxygen required to oxidize 6g of carbon?

univerkov | December 11, 2020 | education

C + O2 = CO2
Over C we write 6 g, under C we write 12 g / mol, over O2 we write x, under O2 we write 22.4 g / mol
We solve through the proportion:
6/12 = x / 22.4
12x = 6 * 22.4
12x = 134.4
x = 134.4 / 12
x = 11.2 (l)
Answer: V (02) = 11.2 l

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