The amount of sodium hydroxide substance formed by the interaction of 2.3 g of sodium with water is equal to?

univerkov | May 5, 2021 | education

1) Formation of sodium hydroxide: 2NaOH + H2 ↑ = 2Na + H2O.

2) The amount of sodium substance: νNa = mNa / MNa, where mNa is the mass of sodium taken (mNa = 2.3 g); MNa is the molar mass of sodium (MNa ≈ 23 g / mol).

Calculation: νNa = mNa / MNa = 2.3 / 23 = 0.1 mol.

3) The ratio of the amount of substance: νNaOH / νNa = 2/2 = 1 and νNaOH = νNa = 0.1 mol.

Answer: The amount of the substance of the obtained sodium hydroxide is 0.1 mol.

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