The amplitude of a body performing harmonic oscillations is 0.5 m. What is the displacement

The amplitude of a body performing harmonic oscillations is 0.5 m. What is the displacement of this body during the period of oscillation?

Since the body performs harmonic vibration, then according to the condition of the problem, the maximum deviation of the body from the initial point is equal to the vibration amplitude – 0.5m. During the period of oscillation, the body will make one complete oscillation, that is, the path traveled by the body will be equal to S = 0.5 * 4 = 2m. But, in this task it is required to find the displacement of the body during the period of oscillation. During the period, the body will return to the starting point and will be in the same place. Therefore, the movement of the body is 0.